x^2+615x-68625=0

Solution for x^2+615x-68625=0 equation:

x^2+615x-68625=0

a = 1; b = 615; c = -68625;
Δ = b2-4ac
Δ = 6152-4·1·(-68625)
Δ = 652725
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{652725}=\sqrt{225*2901}=\sqrt{225}*\sqrt{2901}=15\sqrt{2901}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(615)-15\sqrt{2901}}{2*1}=\frac{-615-15\sqrt{2901}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(615)+15\sqrt{2901}}{2*1}=\frac{-615+15\sqrt{2901}}{2}
$